Abstract
We show that for all integers m >= 4 there exists a 2m x 2m x m latin cuboid that cannot be completed to a 2mx2mx2m latin cube. We also show that for all even m > 2 there exists a (2m-1) x (2m-1) x (m-1) latin cuboid that cannot be extended to any (2m-1) x (2m-1) x m latin cuboid.
Original language | English |
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Pages (from-to) | 239 - 249 |
Number of pages | 11 |
Journal | SIAM Journal on Discrete Mathematics |
Volume | 26 |
Issue number | 1 |
DOIs | |
Publication status | Published - 2012 |